Showing posts with label linear systems substitution. Show all posts
Showing posts with label linear systems substitution. Show all posts

Tuesday, March 25, 2008

More examples of using substitution to solve linear systems


Math Scholars, we are fortunate once again to have some some student work to post to the blog. In this post, you will see that it is not necessary to have both equations in a system in slope intercept form (y=mx+b) to use substitution.

Notice that in example (a), (2x-6) is substituted in for 'y' in the first equation. This allows us to solve for x. Once 'x' is found to be zero, we substitute zero back in for 'x' and solve for 'y'. What a beautiful thing, eh?

If you find that you are still having trouble, please ask me questions in class. There still isn't a better place to get help. :-)

Thursday, March 20, 2008

Using Substitution to solve a linear system


Algebra Scholars, welcome back! Now that you all have become experts at graphing linear systems, it is time to learn how substitution is a really good friend! When graphing isn't the most convienent or doesn't provide you with an exact solution to your linear system, substitution can solve you problems...with your help of course. Check out the example.