Solving Systems with Addition!

Wow, just when you thought systems were the most difficult, complex problem you have ever solved...you got it! Check out this work by one of my students.

This student is demonstrating how to solve linear systems with addition. As long as there is an x in each system that is the opposite of one another (-8x & 8x), they will cancel and become zero. Therefore, we are then able to solve for y. Once we find y, then -3 is substituted back in for y to solve for x. What a great thing!

Remember, up to this point, this method will only work if you have a situation that allows the cancellation of one of the two variables.

Algebra & Geometry 3/31 - 4-4

Spring Break Folks. Enjoy!

More examples of using substitution to solve linear systems

Math Scholars, we are fortunate once again to have some some student work to post to the blog. In this post, you will see that it is not necessary to have both equations in a system in slope intercept form (y=mx+b) to use substitution.

Notice that in example (a), (2x-6) is substituted in for 'y' in the first equation. This allows us to solve for x. Once 'x' is found to be zero, we substitute zero back in for 'x' and solve for 'y'. What a beautiful thing, eh?

If you find that you are still having trouble, please ask me questions in class. There still isn't a better place to get help. :-)

Geometry 3/24 -3/28

Geometry scholars,

This week is the last week of quarter 3. Our test is Friday! If you know you will be gone, your test is on Wednesday as well all of your work and stamp sheet. Be sure you have everything done and ready to be stamped off on Wednesday.

Mr. Hanson

Algebra 3/24 - 3/28

Algebra students,

This week marks the last week in quarter 3.  We have a quiz on Thursday and Friday.  If you know you will be absent, please talk to me in class.  You will need to make up the quiz after spring break.

Mr. Hanson

Using Substitution to solve a linear system

Algebra Scholars, welcome back! Now that you all have become experts at graphing linear systems, it is time to learn how substitution is a really good friend! When graphing isn't the most convienent or doesn't provide you with an exact solution to your linear system, substitution can solve you problems...with your help of course. Check out the example.

What is the solution to a system with Parallel Lines?

Well Algebra Scholars, I am experimenting with posting some classwork completed by students during class while presenting to the entire class.

Solving linear systems can be confusing...especially if you end up with parallel lines. Looking for a point of intersection between two parallel lines can be difficult. :-) No worries, because they don't intersect, there are no solutions! Take a look on the image!

Good Luck with Linear Systems!

Geometry 3/17 - 3/21

Geo folks,

We have our quiz this week in chapter 10.  Otherwise, we keep rolling in surface area and volume.

Mr. Hanson

Algebra 3/17 - 3/21

Algebra scholars,

This week we are finishing up the chapter 8 test and we begin chapter 11.  That's right, chapter 11.  We will come back to chapters 9 and 10 after completing chapter 11.

Have a great week!

Mr. Hanson

Geometry 3/10 - 3/14

Geo scholars,

We just completed chapter 9 and now we are on to chapter 10 this week. 

Have a great week!

Mr. Hanson

Algebra 3/10 - 3/14

Math Scholars,

This week we continue chapter 8.  A day algebra, we are making up the quiz that was missed last week on Monday.

Have a great week.

Mr. Hanson